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n-1 = 9

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Add 1 to both sides:

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n = 10

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Publicfirst time auditions 23

There are \(\boxed{10}\) numbers in the list.**Question:** A sequence of four real numbers forms an arithmetic progression with a common difference \( d \). If the sum of these numbers is 40 and the first term is 7 what are the four numbers?

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Solution:** Let the four terms of the arithmetic progression be \( a a+d a+2d a+3d \). We know the first term \( a = 7 \) and the sum of the numbers is 40. Thus we have:

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Publicfirst time auditions 32

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a + (a+d) + (a+2d) + (a+3d) = 40

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